# -*- coding: utf-8 -*-
'''
Fizz Buzz 问题
给你一个整数n. 从 1 到 n 按照下面的规则打印每个数：
如果这个数被3整除，打印fizz.
如果这个数被5整除，打印buzz.
如果这个数能同时被3和5整除，打印fizz buzz.
样例
比如 n = 15, 返回一个字符串数组：
[
"1", "2", "fizz",
"4", "buzz", "fizz",
"7", "8", "fizz",
"buzz", "11", "fizz",
"13", "14", "fizz buzz"
]
挑战
Can you do it with only one if statement?
'''
class Solution(object):
def fizzBuzz(self, n):
"""
:type n: int
:rtype: List[str]
"""
return [str(i) if (i%3 != 0 and i%5 != 0) else ('Fizz'*(i%3==0) + 'Buzz'*(i%5==0)) for i in range(1, n+1)]
if __name__ == '__main__':
sol = Solution()
res = sol.fizzBuzz(20)
print(res)结果输出：
['1', '2', 'Fizz', '4', 'Buzz', 'Fizz', '7', '8', 'Fizz', 'Buzz', '11', 'Fizz', '13', '14', 'FizzBuzz', '16', '17', 'Fizz', '19', 'Buzz']