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SQLAlchemy 几种查询方式总结

Python   2014-05-04 22:19:32

几种常见sqlalchemy查询:

#简单查询    

print(session.query(User).all())

print(session.query(User.name, User.fullname).all())    

print(session.query(User, User.name).all())        



#带条件查询    

print(session.query(User).filter_by(name='user1').all())    

print(session.query(User).filter(User.name == "user").all())    

print(session.query(User).filter(User.name.like("user%")).all())      


  

#多条件查询    

print(session.query(User).filter(and_(User.name.like("user%"), User.fullname.like("first%"))).all())    

print(session.query(User).filter(or_(User.name.like("user%"), User.password != None)).all())        



#sql过滤    

print(session.query(User).filter("id>:id").params(id=1).all())        



#关联查询     

print(session.query(User, Address).filter(User.id == Address.user_id).all())    

print(session.query(User).join(User.addresses).all())    

print(session.query(User).outerjoin(User.addresses).all())        



#聚合查询    

print(session.query(User.name, func.count('*').label("user_count")).group_by(User.name).all())    

print(session.query(User.name, func.sum(User.id).label("user_id_sum")).group_by(User.name).all())        



#子查询    

stmt = session.query(Address.user_id, func.count('*').label("address_count")).group_by(Address.user_id).subquery()    

print(session.query(User, stmt.c.address_count).outerjoin((stmt, User.id == stmt.c.user_id)).order_by(User.id).all())     


   

#exists    

print(session.query(User).filter(exists().where(Address.user_id == User.id)))    

print(session.query(User).filter(User.addresses.any()))



限制返回字段查询

person = session.query(Person.name, Person.created_at,Person.updated_at).filter_by(name="zhongwei").order_by(Person.created_at).first()



记录总数查询:

from sqlalchemy import func



# count User records, without

# using a subquery.

session.query(func.count(User.id))



# return count of user "id" grouped

# by "name"

session.query(func.count(User.id)).\

        group_by(User.name)



from sqlalchemy import distinct

# count distinct "name" values

session.query(func.count(distinct(User.name)))


select two distinct columns with flask and sqlalchemy

 

SELECT DISTINCT gradelevel, beginningorendtest 

FROM wordlist 

ORDER BY gradelevel,beginningorendoftest

 

the equivalent query:


data = wordlist.query.with_entities(wordlist.gradelevel, wordlist.beginningorendtest)

        .distinct().order_by(wordlist.gradelevel).order_by(wordlist.beginningorendtest)

 



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